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正确代码
- 2024-3-9 13:07:52 @
这里有两个易错点:
十年OI一场空,不开long long见祖宗
还有一个就是转移方程中要改成,因为研究一道题要1分钟
AC代码:
#include <iostream>
#include <algorithm>
#define ll long long
using namespace std;
ll t[2005], f[2005], dp[2005][4005];
int main() {
int n;
cin >> n;
for(int i = 1; i <= n; i++) {
cin >> t[i] >> f[i];
}
for(int i = 0; i <= n; i++) {//初始化
for(int j = 1; j <= 4000; j++) {
dp[i][j] = 1e18;
}
}
for(int i = 1; i <= n; i++) {
for(int j = 0; j <= 4000; j++) {
dp[i][j] = dp[i - 1][j];
if(j >= t[i] + 1) dp[i][j] = min(dp[i - 1][j], dp[i - 1][j - t[i] - 1] + f[i]);//转移方程
}
}
ll minn = 1e18;
for(int i = n; i <= 4000; i++) minn = min(minn, dp[n][i]);
cout << minn << endl;
return 0;
}