- 2022tysc1451 的博客
牛顿迭代法求平方根
- 2025-8-15 14:28:12 @
const double EPSILON=1e-8;
double newton(int n){
double x=n,last_x;
while(abs(x-last_x)>EPSILON){
last_x=x;
x=(x+n/x)/2;
}
return x;
}
const double EPSILON=1e-8;
double newton(int n){
double x=n,last_x;
while(abs(x-last_x)>EPSILON){
last_x=x;
x=(x+n/x)/2;
}
return x;
}